Pleaseeeeeeeeeee help me

Answer:
[tex]\huge\boxed{6x-7y=21}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
[tex]m[/tex] - slope
[tex]b[/tex] - y-intercept (0, b)
We have:
[tex]y=\dfrac{2}{3}x-3\to m=\dfrac{2}{3};\ b=-3[/tex]
From answers:
[tex]6x-7y=21\qquad|-6x\\\\-7y=-6x+21\qquad|:(-7)\\\\y=\dfrac{6}{7}x-3\to m=\dfrac{6}{7};\ \boxed{b=-3}[/tex]
[tex]-\dfrac{2}{3}x+3y=6\qquad|+\dfrac{2}{3}x\\\\3y=\dfrac{2}{3}x+6\qquad|:3\\\\y=\dfrac{2}{9}x+2\to m=\dfrac{2}{9};\ b=2[/tex]
[tex]\dfrac{2}{3}x+3y=-3\qquad|-\dfrac{2}{3}x\\\\3y=-\dfrac{2}{3}x-3\qquad|:3\\\\y=-\dfrac{2}{9}x-1\to m=-\dfrac{2}{9};\ b=-1[/tex]
[tex]x+4y=12\qquad|-x\\\\4y=-x+12\qquad|:4\\\\y=-\dfrac{1}{4}x+3\to m=-\dfrac{1}{4};\ b=3[/tex]