Respuesta :

Answer:

John is correct

Step-by-step explanation:

Let's solve the inequality:

[tex]3x-5\geq28[/tex]

[tex]3x\geq33[/tex]

[tex]x\geq11[/tex]

As we can see, the value of x can be either 11 or anything greater than 11. Since 12 is included in that solution set, John is correct.

takuache182

wait

Step-by-step explanation:

ignore what I just said I was on crack bro