Help Me On These 3 Please



Answer:
see explanation
Step-by-step explanation:
(1)
Using the sine ratio in the right triangle
sin x = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{4}{6}[/tex] , then
x = [tex]sin^{-1}[/tex] ([tex]\frac{4}{6}[/tex] ) ≈ 41.8° ( to the nearest tenth )
(2)
Using the tangent ratio in the right triangle
tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{29}{14}[/tex] , then
x = [tex]tan^{-1}[/tex] ([tex]\frac{29}{14}[/tex] ) ≈ 64.2° ( to the nearest tenth )
(3)
Using the cosine ratio in the right triangle
cos x = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{25}{40}[/tex] , then
x = [tex]cos^{-1}[/tex] ([tex]\frac{25}{40}[/tex] ) ≈ 51.3° ( to the nearest tenth )