Answer:
[(15g NaCl/(70+15)]*100 = % NaCl
{(70g H2O/(70+15)]*100 = % H2O
Explanation:
A solution is prepared by dissolving 15.0 g of table salt in 70.0g of water. (a) The mass percent of solute is 17.64 % and (b) The mass percent of solvent is 82.35 %.
Mass percentage = [tex]\frac{\text{Mass of solute}}{\text{Mass of solute + Mass of solvent}}[/tex] × 100
Mass percentage = [tex]\frac{\text{Mass of solvent}}{\text{Mass of solute + Mass of solvent}}[/tex] × 100
Here,
Mass of solute (table salt) = 15.0 g
Mass of solvent (water) = 70.0 g
(a) The mass percent of solute
Put the value in above formula we get
Mass percentage = [tex]\frac{\text{Mass of solute}}{\text{Mass of solute + Mass of solvent}}[/tex] × 100
= [tex]\frac{15}{15 + 70}[/tex] × 100
= [tex]\frac{15}{85}[/tex] × 100
= 17.64 %
(b) The mass percent of solvent
Mass percentage = [tex]\frac{\text{Mass of solvent}}{\text{Mass of solute + Mass of solvent}}[/tex] × 100
= [tex]\frac{70}{15 + 70} \times 100[/tex]
= [tex]\frac{70}{85} \times 100[/tex]
= 82.35 %
Thus, we can say that (a) The mass percent of solute is 17.64 % and (b) The mass percent of solvent is 82.35 %.
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