Answer:
[tex]x=-\frac{1}{2}[/tex] and [tex]x=-2[/tex]
Step-by-step explanation:
[tex]f(x)=\frac{2x^2+5x+2}{x^2-4x+3}[/tex]
[tex]0=\frac{2x^2+5x+2}{x^2-4x+3}[/tex]
[tex]0=\frac{(2x+1)(x+2)}{(x-1)(x-3)}[/tex]
[tex]0=(2x+1)(x+2)[/tex]
[tex]2x+1=0[/tex] and [tex]x+2=0[/tex]
[tex]x=-\frac{1}{2}[/tex] and [tex]x=-2[/tex]
