Emolife16
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Consider a 0.241 M aqueous solution of sodium hydroxide, NaOH.

A. How many grams of NaOH are dissolved in 24.43 mL?

B. How many individual hydroxide ions (OH-) are found in 24.43 mL?

C. How many moles of sulfuric acid, H2SO4, are neutralized by 24.43 mL of 0.241 M NaOH(aq)?

Respuesta :

henryharrison

Answer:

a. 0.2355052g

Explanation:

a)

1000ml of NaOH contain 0.241moles

24.43ml of NaOH contain (24.43*0.241)/1000 moles

= 0.00588763moles

Relative Molecular Mass of NaOH

= 1*23 + 1*16 + 1*1

= 40

1mole of NaOH weighs 40g

0.00588763moles weigh (0.00588763*40) g

= 0.2355052g

B)

NaOH -> Na+ + -OH

1 mole of NaOH dissociates to form 1 mole of -OH ions

1 mole of a substance contains 6.02*10^23 particles(atoms)

= 0.00588763 * 6.02 *10^23

= ______ions

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