Respuesta :
[tex]3- \dfrac 12 x >10\\\\\implies - \dfrac x 2> 10 -3\\\\\implies -\dfrac x 2 >7\\\\\implies -x > 14\\\\\implies x<-14\\\\\text{Interval solution,}~ (-\infty,-14)[/tex]
[tex]3- \dfrac 12 x >10\\\\\implies - \dfrac x 2> 10 -3\\\\\implies -\dfrac x 2 >7\\\\\implies -x > 14\\\\\implies x<-14\\\\\text{Interval solution,}~ (-\infty,-14)[/tex]