Respuesta :

samueladesida43

There are 0.436 moles of nitrogen dioxide, NO2, present if the reaction conditions are 330 K, 2.46 atm, and 4.8 L.

IDEAL GAS LAW:

The number of moles of nitrogen dioxide (NO2) in this question can be calculated by using the ideal gas law equation as follows:

PV = nRT

Where;

  1. P = pressure (atm)
  2. V = volume (L)
  3. T = temperature (K)
  4. R = gas law constant (0.0821 Latm/molK)
  5. n = number of moles

According to the reaction conditions given in this question;

  1. P = 2.46 atm
  2. V = 4.8L
  3. n = ?
  4. T = 330K

2.46 × 4.8 = n × 0.0821 × 330

11.81 = 27.093n

n = 11.81 ÷ 27.093

n = 0.436mol

Therefore, there are 0.436 moles of nitrogen dioxide, NO2, present if the reaction conditions are 330 K, 2.46 atm, and 4.8 L.

Learn more about the ideal gas law at: https://brainly.com/question/4147359?referrer=searchResults

Otras preguntas