Respuesta :

[tex](3)\\\\17^{\tfrac 43} = \left(17^{\tfrac13\right)^4 = \left(\sqrt[3]{17}\right)^4 =\left(\sqrt[3]{17}\right)^3 \left(\sqrt[3]{17}\right) = 17\sqrt[3]{17}[/tex]

[tex](4)\\\\\text{First term, a= 4,}\\\\\text{Common difference,}~ d =13-4 = 9\\\\\text{nth term} = a+(n-1)d = 4 +(n-1)9 = 4+9n-9 = 9n-5\\\\\text{ 5000th term} = 9(5000) -5 =44995[/tex]