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The volume of a sphere is decreasing at a constant rate of 23 cubic centimeters per
second. At the instant when the volume of the sphere is 7 cubic centimeters, what is
the rate of change of the radius? The volume of a sphere can be found with the
equation V 28. Round your answer to three decimal places.

Respuesta :

abidemiokin

The rate of change of the radius is 1.32cm²/s

The formula for calculating the volume of a sphere is expressed as:

  • [tex]v = \frac{4}{3} \pi r^3[/tex]

The rate of change of the volume is given as:

  • [tex]\frac{dv}{dt} = \frac{dv}{dr} \cdot \frac{dr}{dt} \\\frac{dv}{dt} = =4 \pi r^2 \cdot \frac{dr}{dt} \\[/tex]

Given the following paramters;

dv/dt = 23cm³/s

Volume = 7cm³

Get the radius of the sphere:

7 = 4/3 πr³\

21 = 4πr³

r³ = 21/4π

r = 1.18 cm

Get the rate of change of the radius to have:

[tex]23 = 4(3.14)(1.18)^2 \frac{dr}{dt} \\23 = 17.48 \frac{dr}{dt} \\\frac{dr}{dt}=1.32cm^2/s[/tex]

Hence the rate of change of the radius is 1.32cm²/s

Learn more on volume of a sphere here: https://brainly.com/question/22807400

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