If Kelli and Jarvis maintain a forward force of 524 N for 1.44 seconds on a 158-kg piano, the acceleration will be 0.671 m/s² and the final velocity will be 0.966 m/s.
Kelli and Jarvis exert a force of 524 N on a 158- kg (m) piano.
The friction force, which opposes this force, is 418 N.
The net force (F) is the difference between both forces.
F = 524 N - 418 N = 106 N
We can calculate the acceleration (a) of the piano using Newton's second law of motion.
Newton's second law of motion states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force and inversely proportional to the mass of the object.
a = F/m = 106 N/158kg = 0.671 m/s²
The piano start from rest (u = 0 m/s) and moves with an acceleration of 0.671 m/s² for 1.44 s.
We can calculate its final velocity (v) using the following kinematic equation.
v = u + a × t
v = 0 m/s + 0.671 m/s² × 1.44 s = 0.966 m/s
If Kelli and Jarvis maintain a forward force of 524 N for 1.44 seconds on a 158-kg piano, the acceleration will be 0.671 m/s² and the final velocity will be 0.966 m/s.
Learn more about Newton's second law of motion here: https://brainly.com/question/10673278
