6. If the net investment function is given by
I(t) = 100e0.11
calculate
(a) the capital formation from the end of the second year to the end of the fifth year
(b) the number of years required before the capital stock exceeds $100 000.

Respuesta :

The capital formation of the investment function over a given period is the

accumulated  capital for the period.

  • (a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

  • (b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

[tex]I(t) = 100 \cdot e^{0.1 \cdot t}[/tex]

(a) The capital formation is given as follows;

[tex]\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C[/tex]

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore,  for the three years; Year 3, year 4, and year 5, we have;

[tex]\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87[/tex]

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

[tex]\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000[/tex]

Which gives;

[tex]\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000[/tex]

[tex]\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000[/tex]

[tex]\displaystyle e^{0.1 \cdot t}} = 101[/tex]

[tex]\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15[/tex]

The number of years before the capital stock exceeds $100,00046.15 years.

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