MathsWatch question
please help me

Answer:
2.55°C
Step-by-step explanation:
Calculate the temperature at the 2 given depths
x = 1200
T = [tex]\frac{4500}{1200}[/tex] = 3.75
x = 3750
T = [tex]\frac{4500}{3750}[/tex] = 1.2
Difference in temperature = 3.75 - 1.2 = 2.55°C