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Find the magnitude of the potential difference between two points located 1.2 m apart in a uniform 700 N/C electric field, if a line between the points is parallel to the field. Express your answer in volts.

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asuwafohjames

The magnitude of the potential difference between the two points is 840 V

To solve the problem above, we need to use the formula of Potential difference as related to distance and electric field.

Potential difference: This can be defined as the work required to move a unit charge from a point to another in an electric field.

⇒ Formula:

  •  V = E×d.................. Equation 1

⇒ Where:

  • V = Potential difference
  • E = Electric Field
  • d = Distance

From the question,

⇒ Given:

  • E = 700 N/C
  • d = 1.2 m

⇒ Substitute these values into equation 1

  • V = 700(1.2)
  • V = 840 V

Hence, The magnitude of the potential difference between the two points is 840 V

Learn more about Electric Field here: https://brainly.com/question/11509296

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