Find the equation of a line passing through (-2/3, 5) that is parallel to 4x-2y=6. Express your answer in point-slope form.

Using the information given, it is found that the linear function is given by:
[tex]y - 5 = 2\left(x + \frac{2}{3}\right)[/tex]
A linear equation, in point-slope formula, is modeled by:
[tex]y - y_1 = m(x - x_1)[/tex]
In which:
Parallel to 4x - 2y = 6, which, in standard form is:
[tex]2y = 4x - 6[/tex]
[tex]y = \frac{4}{2}x - \frac{6}{2}[/tex]
[tex]y = 2x - 3[/tex]
Hence, the slope is [tex]m = 3[/tex].
Point [tex]\left(-\frac{2}{3}, 5\right)[/tex], hence, the equation of the line is:
[tex]y - y_1 = m(x - x_1)[/tex]
[tex]y - 5 = 2\left(x + \frac{2}{3}\right)[/tex]
To learn more about linear functions in point-slope form, you can take a look at https://brainly.com/question/13967935