Find the equation of a line passing through (-2/3, 5) that is parallel to 4x-2y=6. Express your answer in point-slope form.

Find the equation of a line passing through 23 5 that is parallel to 4x2y6 Express your answer in pointslope form class=

Respuesta :

Using the information given, it is found that the linear function is given by:

[tex]y - 5 = 2\left(x + \frac{2}{3}\right)[/tex]

A linear equation, in point-slope formula, is modeled by:

[tex]y - y_1 = m(x - x_1)[/tex]

In which:

  • m is the slope.
  • The point is [tex](x_1, y_1)[/tex].
  • If two lines are parallel, they have the same slope.

Parallel to 4x - 2y = 6, which, in standard form is:

[tex]2y = 4x - 6[/tex]

[tex]y = \frac{4}{2}x - \frac{6}{2}[/tex]

[tex]y = 2x - 3[/tex]

Hence, the slope is [tex]m = 3[/tex].

Point [tex]\left(-\frac{2}{3}, 5\right)[/tex], hence, the equation of the line is:

[tex]y - y_1 = m(x - x_1)[/tex]

[tex]y - 5 = 2\left(x + \frac{2}{3}\right)[/tex]

To learn more about linear functions in point-slope form, you can take a look at https://brainly.com/question/13967935