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as the schools sign language interpreter kiran gets paid 35.50 for every parent-teacher conference that he attends. He also gets paid $42 per schhol-related assembly that he attends as an interpreter. If kiran earns $991 for 27 paid events how many parent teacher conferences and how many school related assemblies did he attend write a system of equations describe each variable and solve

Respuesta :

Answer:

x= 22 (number of parent teacher conferences) y=5 (number of school related assemblies)

Step-by-step explanation:

This word problem creates the following system of equations for x = number of parent-teacher conferences and y = number of school related assemblies.

x+y = 27 means that the number of parent teacher conferences plus the number of school related assemblies equals a total of 27 paid events.

35.50x + 42y = 991 means that $35.50 multiplied by a certain number of parent teacher conferences, plus $42 multiplied by a certain number of school related assemblies equals his total earnings of $991.

This sets up the following system

x+y=27

35.50x+42y=991

To solve this, we first need to take the first equation and solve for y.

y=27-x

plug in to the second equation and solve for x.

35.50x+42(27-x)=991

35.50x-42x+1134=991

Collect like terms

-6.5x=-143

divide both sides by -6.5 to solve for x.

x=22

Back substitute into other original equation to solve for y.

22+y=27

y=5

The interpreter attended 22 parent-teacher conference and 5 school related assembly

To solve this problem, we would write out two set of linear equations.

The data given on this problem are

  • parent-teacher conference = $35.50
  • school related assembly = $42
  • The total number of engagements = 27

Let x represent the number of parent-teacher conference

let y represent the number of school related conference

Equations

[tex]x+y = 27...equation (i)\\35.50(x)+42y=991...equation(ii)[/tex]

From equation (i)

[tex]x+y = 27\\x = 27-y...equation(iii)\\[/tex]

Put equation(iii) into equation (ii)

[tex]35.50x+42y=991\\35.50(27-y)+42y=991\\958.50-35.50y+42y=991\\6.50y=991-958.50\\y=5[/tex]

Put y = 5 into equation 1

[tex]x+y=27\\y = 5\\x+5=27\\x=27-5\\x=22[/tex]

From the above calculations, he attended 22 parent-teacher conference and 5 school related assembly.

Learn more on linear equations here;

https://brainly.com/question/4074386

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