Furretturret
contestada

Write the equation of the line that is perpendicular to y=3x-6 and passes through the point
x, y
(2,0)

Perpendicular is the negative reciprocal so the slope is -1/3

Need to know b and the full equation

With work please. Thank you!

Respuesta :

MaxietheTaxi

Answer:

y=-1/3x+2/3 (please mark brainliest)

Step-by-step explanation:

start with y=3x+6

you can get the slope of the perpendicular line by dividing the slope by -1,

so the slope of the new line is -1/3.

using the point and the slope of the new line, we can put it into point-slope form:

y-y₁=m(x-x₁)

y-0=-1/3(x-2)

simplify:

y=-1/3x+2/3

this is the final equation in the form y=mx+b