An object oscillates as it moves along the
X-axis. Its displacement varies with time
according to the equation
x = 4 sin(pi t + pi/6)
where t = time in seconds and
x = displacement in meters
What is the displacement between t= 0
and t = 1 second?

Respuesta :

Using it's formula, it is found that the displacement between t= 0  and t = 1 second is of 0 m.

The equation of motion is given by:

[tex]x(t) = 4\sin{\left(\pi t + \frac{\pi}{6}\right)}[/tex]

The displacement between t= 0  and t = 1 second is given by:

[tex]d = x(1) - x(0)[/tex]

Hence:

[tex]x(1) = 4\sin{\left(\pi + \frac{\pi}{6}\right)} = 4\sin{\left(\frac{7\pi}{6}\right)} = -\frac{4}{2} = -2[/tex]

[tex]x(0) = 4\sin{\left(\frac{\pi}{6}\right)} = \frac{4}{2} = 2[/tex]

Then:

[tex]d = x(1) - x(0) = -2 + 2 = 0[/tex]

The displacement is of 0 m.

You can learn more about displacement at https://brainly.com/question/248054