Using it's formula, it is found that the displacement between t= 0 and t = 1 second is of 0 m.
The equation of motion is given by:
[tex]x(t) = 4\sin{\left(\pi t + \frac{\pi}{6}\right)}[/tex]
The displacement between t= 0 and t = 1 second is given by:
[tex]d = x(1) - x(0)[/tex]
Hence:
[tex]x(1) = 4\sin{\left(\pi + \frac{\pi}{6}\right)} = 4\sin{\left(\frac{7\pi}{6}\right)} = -\frac{4}{2} = -2[/tex]
[tex]x(0) = 4\sin{\left(\frac{\pi}{6}\right)} = \frac{4}{2} = 2[/tex]
Then:
[tex]d = x(1) - x(0) = -2 + 2 = 0[/tex]
The displacement is of 0 m.
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