Answer:
[tex]9\frac{57}{63}[/tex]
Step-by-step explanation:
First, we need to turn them into improper fractions:
[tex]2\frac{4}{7}[/tex] + [tex]7\frac{3}{9}[/tex]
7 x 2 + 4
7 x 9 + 3
[tex]\frac{18}{7}[/tex] + [tex]\frac{66}{9}[/tex]
Next, we need to find a common multiple of both 7 and 9
7, 14, 21, 28, 35, 42, 49, 56, 63
9, 18, 27, 36, 45, 54, 63
So the denomonator turns into 63.
We've multiplied the denomonater 9 times for the first fraction and 7 times for the second fraction, we therefore have to do the same to the numerator.
18 x 9 = 162
66 x 7 = 462
[tex]\frac{162}{63}[/tex] + [tex]\frac{462}{63}[/tex] = [tex]\frac{624}{63}[/tex]
Next, we have to turn it back into a mixed number.
To work it out: 624 / 63 = 9 (1 s.f) <--- Mixed number.
9 x 63 = 567
624 - 567 = 57 (Working out the remainder.)
Combining them, the answer is therefore [tex]9\frac{57}{63}[/tex]
Hope this helps and have a good day!
