The distance from the stadium to Pine Avenue is [tex]13.4miles[/tex], (to the nearest tenth)
The stadium is on Hazel Street(the green line). Pine Avenue is the blue line. The distance from the stadium to Pine Avenue will be the distance on the graph (in miles) from the point representing the stadium, to the point of intersection between Hazel Street and Pine Avenue.
We know the location of the stadium, [tex]S=(-6,6)[/tex]
The point of intersection can be obtained by solving the simultaneous equations
[tex]y=-\dfrac{1}{2}x+3\\y=2x-12[/tex]
since both equations are set equal to [tex]y[/tex], set them equal to each other, to eliminate [tex]y[/tex], and solve for [tex]x[/tex]
[tex]-\dfrac{1}{2}x+3=2x-12\\\\x=6[/tex]
Substitute this value of [tex]x[/tex], into the equation for Pine avenue
[tex]y-2x-12\\=2(6)-12\\=0[/tex]
The point of intersection between Hazel Street and Pine Avenue is [tex]I=(x,y)=(6,0)[/tex]
To compute the distance between the stadium and Pine Avenue, we find the distance between the two points [tex]S[/tex] and [tex]I[/tex]. So,
[tex]d=\sqrt{(6-(-6))^2+(0-6)^2}\\\\=\sqrt{12^2+(-6)^2}\\\\=6\sqrt5\approx13.4\text{ (to the nearest tenth)}[/tex]
The distance is [tex]13.4miles[/tex]
Learn more about coordinate geometry here: https://brainly.com/question/15318780
