A 4.0 kilogram projectile is fired horizontally from a 500 kilogram cannon initially at rest. The momentum of the projectile after being fired is 600 kilogram-meters per second to the north
(neglecting friction).
What is the speed of the cannon after firing?
0.83 m/s
1.2 m/s
o
3.3 m/s
150 m/s

Respuesta :

The speed of the cannon after firing is 1.2 m/s

This can be solved using the law of conservation of momentum.

From the law of conservation of momentum,

⇒ The momentum of the projectile is equal to the momentum of the cannon.

  • MV = P................ Equation 1

⇒ Where :

  • M = mass of the cannon,
  • V = velocity of the cannon
  • P = momentum of the projectile.

⇒ make V the subject of the equation

  • V = P/M.................. Equation 2

From the question,

⇒ Given:

  • P = 600 kgm/s
  • M = 500 kg

⇒ Substitute these values into equation 2

  • V = 600/500
  • V = 1.2 m/s

Hence, The speed of the cannon after firing is 1.2 m/s

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