Respuesta :
Using the z-distribution, it is found that the p-value is of 0.5975.
At the null hypothesis, it is tested if the proportions are equal, that is, their subtraction is 0, hence:
[tex]H_0: p_1 - p_2 = 0[/tex]
At the alternative hypothesis, it is tested if they are different, that is, their subtraction is not 0, hence:
[tex]H_1: p_1 - p_2 \neq 0[/tex]
The sample sizes and proportions are given by:
[tex]n_1 = 631, p_1 = \frac{133}{631} = 0.2108[/tex]
[tex]n_2 = 121, p_2 = \frac{23}{121} = 0.1901[/tex]
The standard errors are given by:
[tex]s_1 = \sqrt{\frac{0.2108(0.7892)}{631}} = 0.0162[/tex]
[tex]s_2 = \sqrt{\frac{0.1908(0.8092)}{121}} = 0.0357[/tex]
For the distribution of differences, the estimate and the standard error are:
[tex]\overline{p} = p_1 - p_2 = 0.2108 - 0.1901 = 0.0207[/tex]
[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{0.0162^2 + 0.0357^2} = 0.0392[/tex]
The test statistic is given by:
[tex]z = \frac{\overline{p} - p}{s}[/tex]
In which [tex]p = 0[/tex] is the value tested at the null hypothesis.
Then:
[tex]z = \frac{\overline{p} - p}{s}[/tex]
[tex]z = \frac{0.0207 - 0}{0.0392}[/tex]
[tex]z = 0.528[/tex]
Using a z-distribution calculator, with a two-tailed test, as we are testing if the mean is different of a value, the p-value is of 0.5975.
A similar problem is given at https://brainly.com/question/25869410
