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A boat heading out to sea starts out at Point AA, at a horizontal distance of 968 feet from a lighthouse/the shore. From that point, the boat’s crew measures the angle of elevation to the lighthouse’s beacon-light from that point to be 7^{\circ} ∘ . At some later time, the crew measures the angle of elevation from point BB to be 3^{\circ} ∘ . Find the distance from point AA to point BB. Round your answer to the nearest tenth of a foot if necessary.

Respuesta :

As the distance from the lighthouse, LH, increases, the angle of elevation,

reduces.

  • The distance from point A to point B is approximately 1,269.9 feet.

Reasons:

The distance of point A from the light house = 968 feet

Angle of elevation from point A to the lighthouse = 7°

Angle of elevation from point B to the lighthouse = 3°

Required:

The distance from point A to point B.

Solution:

[tex]\displaystyle tan(\theta) = \frac{Opposite \, side \, to\, angle}{Adjacent\, side \, to\, angle} = \mathbf{\frac{Height \ from \ sea \ to \ the \ light \ house }{Horizontal \ from \ boat \ to \ the\ LH}}[/tex]

Which gives;

[tex]\displaystyle tan(7^{\circ}) = \mathbf{\frac{Height \ from \ sea \ to \ the \ light \ house }{968 \ feet}}[/tex]

Height to the lighthouse = tan(7°) × 968 feet  ≈ 118.86 feet

From point B, we have;

[tex]\displaystyle tan(3^{\circ}) = \mathbf{ \frac{118.86 \ feet }{Horizontal \ distance \ from \ point \ B\ to \ LH}}[/tex]

Therefore;

[tex]\displaystyle Horizontal \ distance \ from \ boat \ to \ LH = \frac{118.86 \ feet }{tan(3^{\circ})} \approx \mathbf{2237.9 \, feet}[/tex]

Therefore;

Distance from A to B = D

D = Horizontal distance from B to LH - Horizontal distance from A to LH

Distance from A to B = 2237.9 feet - 968 feet ≈ 1269.9 feet

The distance from point A to point B, D ≈ 1,269.9 feet

Learn more about trigonometric ratios here:

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