Respuesta :

abidemiokin

The equation that represents the line that is perpendicular is

3y + 5x = -42

The standard equation of a line in point-slope form is expressed as:

[tex]y-y_1=m(x-x_1)[/tex]

  • m is the slope of the lne
  • (x1, y1) is any point on the line.

  • Given the equation y = 3/2x + 1, the slope of the line is 3/5

  • The slope of the line perpendicular is -5/3

Substitute the point (-12, 6) and the slope m = -5/3 into the equation above to have:

[tex]y-6=-5/3(x-(-12))\\3(y-6)=-5(x+12)\\3y-18=-5x-60\\3y = -5x - 60 + 18\\3y + 5x = -42\\[/tex]

Hence the equation that represents the line that is perpendicular is

3y + 5x = -42

Learn more on equation of a line here:https://brainly.com/question/19417700

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