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The height of a ball when it is thrown off a cliff can be represented by the equation $h=45-7t-6t^2$, where $t$ is time in seconds. In how many seconds will the ball reach a height of 25 feet?

Respuesta :

You want to find t such that

45 - 7t - 6t² = 25

or

6t² + 7t = 20

Solve for t. By completing the square, we have

6t² + 7t = 20

t² + 7/6 t = 10/3

t² + 7/6 t + (7/12)² = 10/3 + (7/12)²

(t + 7/12)² = 529/144

t + 7/12 = ± 23/12

t = -7/12 ± 23/12

t = -5/2   or   t = 4/3

We ignore the negative solution, so the ball reaches a height of 25 feet at t = 4/3 seconds, or about 1.33 seconds after being thrown.