Marla was given the point (1,3), (2, 1), and (-2, -15). She was asked to find a quadratic function that fit these 3 given
points. Marla created a system of three equations with three variables to solve the problem and then used the
matrix functions on her graphing calculator to find the equation. Which equation can be written given these 3
points?

Marla was given the point 13 2 1 and 2 15 She was asked to find a quadratic function that fit these 3 given points Marla created a system of three equations wit class=

Respuesta :

The linear equations [tex]c_{2}+c_{1}+c_{o} = 3[/tex], [tex]4\cdot c_{2} + 2\cdot c_{1}+ c_{o} = 1[/tex] and [tex]4\cdot c_{2} - 2\cdot c_{1} + c_{o} = -15[/tex] can be written given the points [tex](x_{1}, y_{1}) = (1, 3)[/tex], [tex](x_{2}, y_{2}) = (2, 1)[/tex] and [tex](x_{3}, y_{3}) = (-2, -15)[/tex].

A quadratic function ([tex]p(x)[/tex]) is a second order polynomial of the form:

[tex]p(x) = \Sigma\limits_{i= 0}^{2} c_{i}\cdot x^{i} = c_{2}\cdot x^{2}+c_{1}\cdot x + c_{o}[/tex] (1)

Where:

  • [tex]x[/tex] - Independent variable
  • [tex]i[/tex] - Monomial index
  • [tex]c_{i}[/tex] - i-th coefficient

To determine the value of all coefficients, we need three distinct points on plane and create a resulting system of linear equations.

If we know that [tex](x_{1}, y_{1}) = (1, 3)[/tex], [tex](x_{2}, y_{2}) = (2, 1)[/tex] and [tex](x_{3}, y_{3}) = (-2, -15)[/tex], then the system of linear equations is:

[tex]c_{2}+c_{1}+c_{o} = 3[/tex] (2)

[tex]4\cdot c_{2} + 2\cdot c_{1}+ c_{o} = 1[/tex] (3)

[tex]4\cdot c_{2} - 2\cdot c_{1} + c_{o} = -15[/tex] (4)

The linear equations [tex]c_{2}+c_{1}+c_{o} = 3[/tex], [tex]4\cdot c_{2} + 2\cdot c_{1}+ c_{o} = 1[/tex] and [tex]4\cdot c_{2} - 2\cdot c_{1} + c_{o} = -15[/tex] can be written given the points [tex](x_{1}, y_{1}) = (1, 3)[/tex], [tex](x_{2}, y_{2}) = (2, 1)[/tex] and [tex](x_{3}, y_{3}) = (-2, -15)[/tex].

To learn more on systems of linear equations, we kindly invite to check this verified question: https://brainly.com/question/20379472