56.2 m
Step-by-step explanation:
We can solve for the maximum height by calculating the derivative of y with respect to time and then equating it to zero, i.e.,
[tex]\dfrac{dy}{dt} = 0[/tex]
then solve for the time t that satisfies the equation above. The expression for the height y is
[tex]y = 60t - 16t^2[/tex]
Taking the derivative of this expression, we get
[tex]\dfrac{dy}{dt} = 60 - 32t = 0 \Rightarrow t = \dfrac{60}{32} = 1.9\:\text{s}[/tex]
This means that at t = 1.9 s, the ball would have reached its maximum height. To determine this height, use this value for t in the the equation for y to get
[tex]y = 60(1.9\:\text{s}) - 16(1.9\:\text{s})^2 = 56.2\:\text{m}[/tex]
