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Which quadratic equation is equivalent to (x + 2)2 + 5(x + 2) – 6 = 0?
(u + 2)2 + 5(u + 2) – 6 = 0 where u = (x – 2)
u2 + 4 + 5u – 6 = 0 where u = (x – 2)
u2 + 5u – 6 = 0 where u = (x + 2)
u2 + u – 6 = 0 where u = (x + 2)

Respuesta :

ranjot0143

Answer:

we have

(x+2)^{2} +5(x+2)-6=0(x+2)

2

+5(x+2)−6=0

Let

u=(x+2)u=(x+2)

Substitute in the expression

(u)^{2} +5(u)-6=0(u)

2

+5(u)−6=0

therefore

the answer is

(u)^{2} +5(u)-6=0(u)

2

+5(u)−6=0 is equivalent to (x+2)^{2} +5(x+2)-6=0(x+2)

2

+5(x+2)−6=0

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