Respuesta :

  • Here, RY = PY.
  • Angle QRY = Angle QPY = 90°
  • QY = QY [common]
  • Therefore, ∆ QRY = ∆ QPY
  • By c.p.c.t., angle RQY = angle PQY
  • Therefore,
  • [tex]16x - 27 = 5x + 6 \\ = > 16x - 5x = 6 + 27 \\ = > 11x = 33 \\ = > x = 3[/tex]
  • Therefore, the measure of angle YQR
  • [tex] = (16x - 27)° \\ = (16 \times 3 - 27)° \\ = (48 - 27)° \\ = 21°[/tex]

Answers:

  1. 3
  2. 21°

Hope you could get an idea from here.

Doubt clarification - use comment section.

[tex]\\ \tt\Rrightarrow 16x-27=5x+6[/tex]

[tex]\\ \tt\Rrightarrow 16x-5x=6+27[/tex]

[tex]\\ \tt\Rrightarrow 11x=33[/tex]

[tex]\\ \tt\Rrightarrow x=3[/tex]

  • m<YQR=16(3)-27=48-27=21°