Respuesta :
The product of a rational number and an irrational number is an irrational
number.
The correctly completed proof is presented as follows;
To prove that 4·π is irrational, with the assumption that, 4·π = [tex]\displaystyle \frac{a}{b}[/tex], where b ≠ 0. Which by isolation of π gives π = [tex]\displaystyle \mathbf{ \frac{a}{4 \cdot b}}[/tex].
The right side of the equation is irrational, because the left side of the
equation is irrational, this is a contradiction.
Therefore, the assumption is wrong and the number 4·π is irrational.
Reasons:
The proof is presented as follows;
With the assumption that 4·π is rational, we have;
[tex]\displaystyle 4 \cdot \pi = \mathbf{\frac{a}{b}}[/tex]
Where;
b ≠ 0
Making π the subject of the above formula, by isolating, it, we have;
[tex]\displaystyle \pi = \mathbf{\frac{a}{4 \cdot b}}[/tex]
The right side of the equation is rational, however, the left side of the
equation π is irrational, which results in a contradiction, therefore, the
product 4·π is an irrational number.
Learn more about irrational numbers here:
https://brainly.com/question/1625874
