Respuesta :
Answer:
This problem is easy but I'll demonstrate an approach for simplifying these kind of problems that can be applied to problems of higher complexity.
Key: Notice that you can write AH as 10A + H and HEE as 100H + 10E+E, and thus
AH +A = HEE
10A + H + A = 100H + 10E +E
11A + H = 100H + 11E
11A = 99H + 11E
A = 9H + E
As H can not be 0 (it is the leading digit in HEE), A must be at least and therefore exactly 9 and the problem solves itself from there on.
Answer:
This problem is easy but I'll demonstrate an approach for simplifying these kind of problems that can be applied to problems of higher complexity.
Key: Notice that you can write AH as 10A + H and HEE as 100H + 10E+E, and thus
AH +A = HEE
10A + H + A = 100H + 10E +E
11A + H = 100H + 11E
11A = 99H + 11E
A = 9H + E
As H can not be 0 (it is the leading digit in HEE), A must be at least and therefore exactly 9 and the problem solves itself from there on.
Step-by-step explanation: