Factor 26r3s 52r5 â€"" 39r2s4. What is the resulting expression? 13(2r3s 4r5 â€"" 3r2s4) 13r2s(2r 4r3 â€"" 3s3) 13r2(2rs 4r3 â€"" 3s4) 13r2(26r3s 52r5 â€"" 39r2s4).

Respuesta :

The resulting expression from the factorization of 26r³s + 52r^(5) - 39r²s⁴ is; 13r²(2rs + 4r³ - 3s⁴)

We want to factor the algebraic expression;

26r³s + 52r^(5) - 39r²s⁴

Now, we need to first find the highest common factor here and factorize out.

First of all for the letters;

The highest common factor of the letters is r²

Factors of 26 = 1, 2, 13, 26

Factors of 39 = 1, 3, 13, 39

Factors of 52 = 1, 2, 4, 13, 26, 52

The highest common factor for the 3 numbers is 13.

Thus,in total, the highest common factor for the algebraic expression is 13r².

Finally, we have;

13r²(2rs + 4r³ - 3s⁴)

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