Answer:
QUESTION 1
The image attached shows the graph of the given system of equations. There you would notice that the solution is (-1,-5), which is the interception point.
To verify the solution algebraically, we need to multiply the first equation with -1 and then sum them up
Then, we use this value to find the other one
Therefore, the solution is (-1,-5), which is the same showed graphically.
QUESTION 2.
Using the same process as we did in the QUESTION 1. The image attached shows both lines and the interception point which is the solution. So, the solution is (6,0).
To verify the solution algebraically, we must multiply the second equation by -6
Then, we use this value to find the other one
Therefore, the solution is (6,0), the same showed graphically.
Step-by-step explanation:
If you don't get it
question 1
solution is (-1,-5)
question 2
solution is (6,0),
The solution to the system of linear equations x+6y=6 and y=1/3 x−2 is x = 6 and y = 0.
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have:
The system of linear equations:
x+6y=6
y=1/3 x−2
Part A: Graph is shown in the picture.
Part B: The intersection point is (6, 0)
x = 6
y =0
Part C: By substitution method.
[tex]\rm x+6\left(\dfrac{x}{3}-2\right)=6[/tex]
x = 6
y = 0
Thus, the solution to the system of linear equations x+6y=6 and y=1/3 x−2 is x = 6 and y = 0.
Learn more about the linear equation here:
brainly.com/question/11897796
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