[tex]2x +y = 20~~....(i)\\\\6x -5y = -4~~....(ii)\\\\\\\text{Multiply equation (i) by 3:}\\\\6x +3y = 60~~...(iii)\\\\(iii)-(ii):\\\\6x+3y - 6x+5y = 60-(-4)\\\\\implies 8y = 60+4 = 64\\\\\implies y = \dfrac{64}8\\\\\implies y = 8\\\\\\\text{Substitute y =8 in equation (i):}\\\\2x+8 =20\\\\\implies 2x = 20-8 = 12\\\\\implies x = \dfrac{12}2 = 6\\\\\text{Hence (x,y) = (6, 8)}[/tex]
