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The combined area of the photo and mat needs to be 224 square inches. The equation that represents the combined area is
(2w +8)(2w + 10) = 224, where w represents the width of the mat around the photo.
What should the width of the mat be?
Enter your answer as the correct value, including units, like this: 42 meters
Be sure to use the correct units from the context of the problem

Respuesta :

The width of the mat around the photo is 3 inches

The combined area of the of the photo and math = 224 square inches

The combined area is represented as:

(2w +8)(2w + 10) = 224

Expand the equation using the distributive rule

[tex]4w^2+20w+16w+80=224\\\\4w^2+36w+80-224=0\\\\4w^2+36w-144=0[/tex]

Divide through by 4

[tex]w^2+9w-36=0[/tex]

Factorize the resulting quadratic equation to solve for w

[tex]w^2-3w+12w-36=0\\\\w(w-3)+12(w-3)=0\\\\(w-3)(w+12)=0[/tex]

w  -  3  =  0

w   =  3

w  +  12  =  0

w   =  -12

The width of the mat around the photo is 3 inches

Learn more on area here: https://brainly.com/question/20968176

adioabiola

The width of the mat around the photo is 3 inches

Combined area:

2w +8)(2w + 10) = 224

where,

w = width of the mat around the photo

(2w +8)(2w + 10) = 224

open parenthesis

4w² + 20w + 16w + 80 = 224

4w² + 36w + 80 - 224 = 0

4w² + 36w - 144 = 0

divide through by 4

w² + 9w - 36 = 0

solve quadratic equation using factorization method

w² + 12w - 3w - 36 = 0

w(w + 12) - 3(w + 12) = 0

(w + 12) (w - 3) = 0

w + 12 = 0 or w - 3 = 0

w = -12 or w = 3

The width of the mat around the photo cannot be a negative value.

Therefore, the width of the mat around the photo is 3 inches

Learn more about quadratic equation:

https://brainly.com/question/1214333

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