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The diagram below shows a child pulling a 50.-kg friend on a 20 kg sled by applying a 300. newton force on the sled rope at an angle of 40 degrees with the horizontal. The sled moves at constant velocity as the person pulls with the 300 N force.

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onyebuchinnaji

The vertical component of the applied force on the sled is 192.84 N.

The given parameters:

  • Mass of the friend, M = 50 kg
  • Mass of the sled, m = 20 kg
  • Applied force, F = 300 N
  • Inclination of the force, θ = 40 ⁰

The vertical component of the 300 N force is calculated as follows;

[tex]F_y= F \times sin(\theta)\\\\F_y = 300 \times sin(40)\\\\F_y = 192.84 \ N[/tex]

Thus, the vertical component of the applied force on the sled is 192.84 N.

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The vertical component of the 300 N force is approximately?

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