The equation of the line is [tex]y=8[/tex]
To get the required equation, use the general form of the equation of a line having a gradient [tex]m[/tex], and passing through a point [tex](x_0,y_0)[/tex]
[tex]y-y_0=m(x-x_0)[/tex]
For our problem, the line has [tex]0[/tex] gradient, and passes through the point [tex](4,8)[/tex]
substituting the required values, we have
[tex]y-y_0=m(x-x_0)\\y-8=0(x-4)\\y-8=0\\y=8[/tex]
The required equation is [tex]y=8[/tex]
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