If CD = 6 and the perimeter of ABC is 41, what is the perimeter of ABE?

Answer:
53.
Step-by-step explanation:
DE = CD = 6 ( as triangle ACE is isosceles so AD is the perpendicular bisector of CE.
Therefore CE = 12.
AB + BC + AC = 41 (given perimeter of ABC)
AB + BC + AE + 12 = perimeter of ABE.
But AE = AC ( given), so
AB + BC + AC + 12 = perimeter of ABE
Now we know that AB + BC + AC = 41 , so
41+ 12 = perimeter of ABE.