Andrew is painting a wall on the side of his house. He has a 20 foot ladder wich makes a 79 degree angle with the ground. Standing on the second to past rung of the ladder, Andrew can reach 5 feet above the point where the ladder rests against the wall. How high up the wall can Andrew paint

Respuesta :

Andrew can reach a maximum of [tex]24.6ft[/tex] high up the wall.

The right-angled triangle formed can be solved using the [tex]sine[/tex] ratio. that is

[tex]sin(72^\circ})=\dfrac{h}{20}[/tex]

where [tex]h[/tex] is the distance from the foot of the wall to the tip of the ladder where it rests on the wall. Substituting, and solving for [tex]h[/tex], we get

[tex]0.9816=\dfrac{h}{20}\\\\h=20\times0.9816\\\\h=19.632ft[/tex]

Since Andrew can reach an extra [tex]5ft[/tex] above the point where the ladder rests against the wall, the maximum height Andrew can paint is

[tex](19.632+5)ft=24.632ft\\\\\approx24.6ft[/tex]

Another solved word problem on trigonometry can be found here: https://brainly.com/question/12146092