For #8 and #9, fill in the missing information for the following trapezoids. SHOW YOUR WORK to solve for the missing value.

9.
height = ________
b1 = 20 cm
b2 = 21 cm
area = 205 cm2

Respuesta :

Applying the equation for the area of the trapezoid, it is found that the height is of 10 cm.

The area of a trapezoid is half the multiplication of the sum of the bases and the height, that is:

[tex]A = \frac{h}{2}(b_1 + b_2)[/tex]

For this problem, we have that: [tex]A = 205, b_1 = 20, b_2 = 21[/tex], hence:

[tex]A = \frac{h}{2}(b_1 + b_2)[/tex]

[tex]205 = \frac{h}{2}(20 + 21)[/tex]

[tex]20.5h = 205[/tex]

[tex]h = \frac{205}{20.5}[/tex]

[tex]h = 10[/tex]

The height is of 10 cm.

To learn more about area of a trapezoid, https://brainly.com/question/9918120

Answer:

The height of trapezoid is 10 cm.

Step-by-step explanation:

Given :

  • »» [tex]\rm{b_1}[/tex] = 20 cm
  • »» [tex]\rm{b_2}[/tex] = 21 cm
  • »» [tex]\rm{area}[/tex] = 205 cm²

To Find :

  • »» Height of trapezoid

Using Formula :

[tex]{\star{\small{\underline{\boxed{\sf{\red{Area_{(Trapezoid)} = \dfrac{1}{2} \Big(b_1 + b_2\Big)h}}}}}}}[/tex]

  • ✧ [tex]\rm{b_1}[/tex] = 20 cm
  • ✧ [tex]\rm{b_2}[/tex] = 21 cm
  • ✧ [tex]\rm{area}[/tex] = 205 cm²

Solution :

Substituting all the given values in the formula to find height of trapezoid :

[tex]{\dashrightarrow{\small{\sf{Area_{(Trapezoid)} = \dfrac{1}{2} \Big(b_1 + b_2\Big)h}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{205 = \dfrac{1}{2} \Big(20 + 21\Big)h}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{205 = \dfrac{1}{2} \Big( \: 41 \: \Big)h}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{205 = \dfrac{1}{2} \times 41 \times h}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{205 = \dfrac{ 41}{2}\times h}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{h = 205 \times \dfrac{2}{41}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{h = \cancel{205} \times \dfrac{2}{\cancel{41}}}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{h =5 \times 2}}}}[/tex]

[tex]{\dashrightarrow{\small{\sf{h =10 \: cm}}}}[/tex]

[tex]{\star{\small{\underline{\boxed{\frak{\pink{h =10 \: cm}}}}}}}[/tex]

Hence, the height of trapezoid is 10 cm.

[tex]\rule{300}{1.5}[/tex]