Respuesta :
Answer:
900N, charges repel
Explanation:
F = KQq/d²
K = 9 × 10^9Nm²/C²
Q= 10mC = 10 × 10^-3C
q = 1mc = 1 × 10^-3C
d = 10m
F = ?
Force = (9 × 10^9 × 10 × 10^-3 × 1 × 10^-3)/10²
= 9 × 10²
= 900N
It will be an electrostatic force of repulsion since like charges(two positive charges) repel
The magnitude and the direction of the electrostatic force between the charges will be 900N and the charges will repel each other.
What is Coulomb's law of forces?
Coulomb's law states that whenever the two charged particles are separated by a particular distance then there will be a force of attraction or repulsion acts between the charge.
The formula of coulomb's force will be given by
[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]
[tex]K=9\times 10^9\ \frac{Nm^2}{C^2}[/tex]
[tex]q_1= 10\times 10^{-3}\ C[/tex]
[tex]q_2=1\times 10^{-3}\ C[/tex]
[tex]\rm Distance \ d=10 \ m[/tex]
Now the force will be calculated as
[tex]F=(9\times 10^9)\dfrac{(10\times 10^{-3})\times (1\times 10^{-3})}{10}[/tex]
[tex]F= 900\ N[/tex]
The charges are positive in nature so they will repel each other
Hence the magnitude and the direction of the electrostatic force between the charges will be 900N and the charges will repel each other.
To know more about coulomb's law follow
https://brainly.com/question/506926