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You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute below? (Ar:H51,Li57,N514,O516,Mg524,S532.)
a lithium sulfate, Li2SO4

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transitionstate

Answer:

             0.045 L  or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

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