The triangles formed by the path of the ball and the wall in the given diagram are similar triangles.
The point on the wall she should aim is; A. 7.8 feet away from point B
The possible diagram in the question is attached
Let x represent the distance from point B where the ball lands.
ΔCDE is similar to ΔABE, by Angle-Angle similarity postulate.
By trigonometric ratio, the tangent of the angles ∠CDE and ∠BAE are;
[tex]tan(\angle CDE) = \mathbf{\dfrac{20 - x}{25}}[/tex]
[tex]tan(\angle BAE) = \mathbf{ \dfrac{x}{16}}[/tex]
tan(∠CDE) = tan(∠BAE)
Therefore;
[tex]\dfrac{20 - x}{25} = \dfrac{x}{16}[/tex]
Which gives;
16 × (20 - x) = 25·x
320 = 41·x
x = 320 ÷ 41 ≈ 7.8
The point on the wall she should aim if she's standing at point A is therefore;
Learn more about trigonometric ratios here:
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