Respuesta :

abidemiokin

The measure of the EF and x from the given diagram is 58 and 7 respectively.

Bisection of lines

4) From the given diagram;

  • DF = DE + EF

9x - 39 = 47 + 3x + 10

9x - 3x = 57 + 39

6x = 96

x = 96/6

x = 16

Get the value of EF

EF = 3x + 10

EF = 3(16) + 10

EF = 58

The mesure of EF is 58

5) HJ = HI + IJ

7x - 27 = 3x - 5 + x - 1

7x - 27 = 4x - 6

7x - 4x = -6 + 27

3x = 21

x = 7

Hence the value of x is 7

Learn more on bisection here: https://brainly.com/question/25770607

Th value of x when HJ = 7x - 27 is 7

Base on the line segment HJ:

  • HI + IJ = HJ

HI = 3x - 5

IJ = x - 1

Therefore,

HJ  = 3x- 5 + x - 1

7x - 27 = 4x - 6

7x - 4x = -6 + 27

3x = 21

divide both sides by 3

x = 21 / 3

x = 7

The value of x is 7

learn more on lines here: https://brainly.com/question/24672602?referrer=searchResults

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