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A merry-go-round rotates with a centripetal acceleration of 21 m/s2. If the
outer horses are 10 m from the center of the ride, what is their velocity?
O A. 17.1 m/s
O B. 16.8 m/s
C. 14.5 m/s
D. 15.2 m/s

Respuesta :

Lanuel

The velocity of this merry-go-round that rotates around a center is equal to: C. 14.5 m/s.

Given the following data:

  • Radius = 10 meters
  • Centripetal acceleration = 21 [tex]m/s^2[/tex]

To determine the velocity of this merry-go-round that rotates around a center:

The formula for centripetal acceleration.

Mathematically, the centripetal acceleration of an object is given by the formula:

[tex]A_c = \frac{V^2}{r}[/tex]

Where:

  • [tex]A_c[/tex] is the centripetal acceleration.
  • r is the radius of a circular track.
  • V is the velocity of an object.

Making V the subject of formula, we have:

[tex]V=\sqrt{A_cr}[/tex]

Substituting the given parameters into the formula, we have;

[tex]V=\sqrt{21 \times 10}\\\\V=\sqrt{210}[/tex]

V = 14.5 m/s.

Read more on centripetal acceleration here: https://brainly.com/question/2788500

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