The divisibility rule of 6 is that when the given number is divisible by both 2 & 3 then it is also divisible by 6.
[tex]\rule{300pt}{3pt}[/tex]
Let's check with 2 first of all
[tex]60714298[/tex]
- It is divisible by 2, Because the last of digit of number is even i.e. 8
Let's check for 3 now
[tex]60714298 \\ 6 + 0 + 7 + 1 + 4 + 2 + 9 + 8 = 27 \\ 27 \div 3 = 9[/tex]
- Yes, It is divisible by 3, Because the sum of digits in the given number is divisible by 3.
The number is divisible by both 2 & 3. Thus, making it divisible by 6 also.
