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Answer:

y = -3x - 4

Step-by-step explanation:

so 3y = x - 4 => y = 1/3x - 4/3

Perpendicular lines have slopes that are negative reciprocals of one another

so slope of perpendicular line is -3

so y = mx + b

y = -3x + b

Using (-2,2)

2 = -3(-2) + b

2 = 6 + b

b = -4

so y = -3x - 4

The equation of the line perpendicular to 3y = x - 4 passes through the point (-2,2) is y = -3x - 4.

What is equation of line?

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Let, 3y = x - 4

Dividing throughout by 3, we get

y = 1/3x - 4/3

Perpendicular lines have slopes that exist as negative reciprocals of one another.

The slope of the perpendicular line exists at -3.

so y = mx + b

y = -3x + b

Let, y = 2, m = (-3), x = (-2), b = ?

Using the points (-2,2)

2 = -3(-2) + b

2 = 6 + b

b = -4

Therefore, the equation of the line perpendicular to 3y = x - 4 passes through the point (-2,2) is y = -3x - 4.

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