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Solve :- Ques 5 ) (a) .

• Question refer to the attachment .


• Notes :

Need Genuine Answer .
Answer will be with Explanation .


Otherwise , spam answer will be report !!
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Solve Ques 5 a Question refer to the attachment Notes Need Genuine Answer Answer will be with Explanation Otherwise spam answer will be report class=

Respuesta :

ItsYourDeepak254

Answer:

Hey There!

Let's solve...

We have

[tex] \angle \: odb = \angle \: cao \\ \\ \angle \: dbo = \angle \: aco \\ \\ [/tex]

Using AA Criterion of Similarity we have

[tex] \triangle \: obd \: - \triangle \: oac \\ \\ [/tex]

This implies that

[tex] \frac{od}{ob} = \frac{oa}{oc} \to \frac{6}{3 + 2 } \: or \: \frac{6}{5} = \frac{oa}{oc} \\ \\ \to \: oa = \frac{6}{5} oc [/tex]

Now,

[tex]ab = ao - bo \\ \\ = \frac{6}{5}oc - bo = \frac{6}{5}(od - oc) \\ - bo \\ \\ = \frac{6}{5}(6 + 4cm) - 5cm \\ \\ = 7cm [/tex]

Note:Every letters should be in capital, i don't have any option here so i can't do.

I hope it is helpful to you...

Cheers!_________

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