[tex] {3}^{x + 2} + 3 ^{x + 1} = \frac{4}{3} \\ = > {3}^{x} \times {3}^{2} + {3}^{x} \times 3 = \frac{4}{3} \\ = > {3}^{x} \times 9 + {3}^{x} \times 3 = \frac{4}{3} \\ = > {3}^{x} (9 + 3) = \frac{4}{3} \\ = > {3}^{x} \times 12 = \frac{4}{3} \\ = > {3}^{x} = \frac{4}{3} \times \frac{1}{12} \\ = > {3}^{x} = \frac{1}{3 \times 3} \\ = > {3}^{x} = {3}^{ - 2} \\ = > x = - 2[/tex]
Answer:
x = -2
Hope you could understand.
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