Answer:
Length of smaller square: 4
Length of larger square √32 or 5.66
Area of smaller square: 16
Area of larger square: 32
Step-by-step explanation:
See attachment
The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.
So for triangle ABD, the length from (-2,2) to (2,2) equals of 1/2 of AD: 8/2 = 4
so the areas of smaller square is 4 x 4 = 16
And for triangle ABD, AD^2 = AB^2 + BD^2
since AB = BD => AD^2 = 2AB^2
AB^2 = (AD^2)/2 = (8^2)/2 = 64/2 = 32
AB = √32
so the area of larger square = (√32)(√32) = 32
Hope this helps
